4sin^2x+2cos^2x=5

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Solution for 4sin^2x+2cos^2x=5 equation: 


Simplifying
4sin2x + 2cos2x = 5

Reorder the terms:
2cos2x + 4in2sx = 5

Solving
2cos2x + 4in2sx = 5

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4in2sx' to each side of the equation.
2cos2x + 4in2sx + -4in2sx = 5 + -4in2sx

Combine like terms: 4in2sx + -4in2sx = 0
2cos2x + 0 = 5 + -4in2sx
2cos2x = 5 + -4in2sx

Divide each side by '2os2x'.
c = 2.5o-1s-2x-1 + -2in2o-1s-1

Simplifying
c = 2.5o-1s-2x-1 + -2in2o-1s-1

Reorder the terms:
c = -2in2o-1s-1 + 2.5o-1s-2x-1

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